-x^2+10x+144=0

Solution for -x^2+10x+144=0 equation:

-x^2+10x+144=0

We add all the numbers together, and all the variables

-1x^2+10x+144=0

a = -1; b = 10; c = +144;
Δ = b2-4ac
Δ = 102-4·(-1)·144
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-26}{2*-1}=\frac{-36}{-2}
=+18
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+26}{2*-1}=\frac{16}{-2}
=-8
$